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A circular coil of 25 turns and radius of 12 cm is placed in a uniform magnetic field of 0.5 T normal to the plane of coil. If the current in the coil is 5 A, then total torque experienced by the coil isA. 1.5NmB. 2.5NmC. 3.5NmD. zero

Answer» Correct Answer - D
Here, n=25turns, r=12cm, B=0.5T
Since the coil is placed in uniform magnetic field normal to the plane of the coil. Hence the anlge between magnetic moment and magnetic field direction is zero `(i.e. theta=0)`
`therefore pi=mB sin theta=mB sin theta`
`Rightarrow tau=0`


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