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A circular coil of 25 turns and radius of 12 cm is placed in a uniform magnetic field of 0.5 T normal to the plane of coil. If the current in the coil is 5 A, then total torque experienced by the coil isA. 1.5NmB. 2.5NmC. 3.5NmD. zero |
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Answer» Correct Answer - D Here, n=25turns, r=12cm, B=0.5T Since the coil is placed in uniform magnetic field normal to the plane of the coil. Hence the anlge between magnetic moment and magnetic field direction is zero `(i.e. theta=0)` `therefore pi=mB sin theta=mB sin theta` `Rightarrow tau=0` |
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