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A circular coil of 5 turns and of 10 cm mean diameter is connected to a voltage source. If the resistance of the coil is 10Omega , the voltage of the source so as to nullify the horizontal component of the earth's magnetic field at 30 A turn m^(-1) at the center of the coil should be |
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Answer» 6V, plane of the coil NORMAL to MAGNETIC meridian Field at centre, `B=(mu_(0)NI)/(2a) = (mu_(0)N)/(2a) xx V/R` `THEREFORE V= (2aRB)/(mu_(0)N)` `=2 xx (5 xx 10^(-2)) xx 10 xx (30 xx 4pi xx 10^(-7))/((4pi xx 10^(-7)) xx 5)` = 6 volt. To NULLIFY the horizontal component of magnetic field of the earth, plane of the coil should be normal to magnetic meridian. |
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