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A circular coil of 500 turns of wire has an enclosed area of 0.1m^2per turn. It is kept perpendicular to a magnetic field of induction 0.27 and rotated by 180^@about a diameter perpendicular to the field in 0.1 s. How much charge will pass when the coil is connected to a galvanometer with a combined resistance of 50Omega |
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Answer» SOLUTION :`q = (phi_i - phi_f)/( R) = (NBA - (-NBA) )/( R) = (2NBA)/( R)` ` q = (2 XX 500 xx 0.2 xx 0.1)/(50) = 0.4 C` |
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