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A circular coil of 500 turns of wire has an enclosed area of 0.1 m^(2) per turn. It is kept perpendicular to a magnetic field of induction 0.27 and rotated by 180^(@) about a diameter perpendicular to the field in 0.1 s. How much charge will pass when the coil is connected to a galvanometer with a combined resistance of 50 Omega. |
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Answer» SOLUTION :`q=(phi_(i)-phi_(F))/(R)=(NBA-(-NBA))/(R)=(2NBA)/(R)` `q=(2 XX 500 xx 0.2 xx 0.1)/(50)` = 0.4 C. |
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