1.

A circular coil of radius 0.1 m has 80 turns of wire. If the magnetic field through the coil increases from 0 to 2 tesla in 0.4 sec and the coil is connected to a 11 ohm resistor, what is the current (in A) flow through the resistor during the 0.4 sec?

Answer»

(8/7)
(7/8)
8
7

Solution :`|epsi|=N (dphi)/(dt) = NA(dB)/(dt) = 80 xx 22/7 xx (0.1)^2 ((2.0)/(0.4))`
`I = (|epsi|)/(R ) = 80 xx 22/7 xx ((0.1)^2 xx 5)/(11) = 8/7 A`


Discussion

No Comment Found

Related InterviewSolutions