1.

A circular coil of radius 10 cm, 500 turns and resistance 2Omega is placed with its plane, perpendicular to the horizontal component of the earth's magnetic field. It is rotated about its vertical diameter through 180^@ in 0.25 s. The induced e.m.f. in the coil is ..... (Take H_E=3.0xx10^(-5) T)

Answer»

`6.6xx10^(-4)` V
`1.4xx10^(-2)` V
`2.6xx10^(-2)` V
`3.8xx10^(-3)` V

Solution :`DELTAPHI=NAB cos 180^@ - NAB cos 0^@`
=NAB(-1)-NAB
=-2NAB
`epsilon=-(Deltaphi)/(Deltat)`
`=(2NAB)/(Deltat)`
`=(2xx500xx3.14xx(10xx10^(-2))^2 xx 3xx10^(-5))/0.25`
`=(1000xx3.14xx10^(-2)xx3xx10^(-5))/(25xx10^(-2))`
`=376.8xx10^(-5) APPROX 3.8xx10^(-3)` V


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