A circular coil of wire consisting of 100 turns, each of radius 4.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil ?

A circular coil of wire consisting of 100 turns, each of radius 4.0 cm

1.	A circular coil of wire consisting of 100 turns, each of radius 4.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil ?
Answer» Solution :For a CURRENT carrying thin circular COIL of radius R with N no. of IDENTICAL tightly wound turns, magnetic field produced at the centre is, `B=(mu_(0)NI)/(2R)` `thereforeB=((4pixx10^(-7))(100)(0.4))/((2)(0.08))` `thereforeB=pixx10^(-4)T=3.14xx10^(-4)T`

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A circular coil of wire consisting of 100 turns, each of radius 4.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil ?

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