A circular coil with radius 10 cm and 10 no. of tightly wound identical turns is kept perpendicular to uniform magnetic field 2 xx 10^(-4)G intensity. Now, it is rotated with angular velocity 2pi "rad s"^(-1) about an axis passing through it but perpendicular to magnetic field. Then, at ........s, least time magnetic flux passing through it becomes half of maximum magnetic flux.

A circular coil with radius 10 cm and 10 no. of tightly wound identica

1.	A circular coil with radius 10 cm and 10 no. of tightly wound identical turns is kept perpendicular to uniform magnetic field 2 xx 10^(-4)G intensity. Now, it is rotated with angular velocity 2pi "rad s"^(-1) about an axis passing through it but perpendicular to magnetic field. Then, at ........s, least time magnetic flux passing through it becomes half of maximum magnetic flux.
Answer» `1/2` `1/12` `1/6` `1/4` SOLUTION :We have `Phi=NAB COS (OMEGAT)`…(1) `THEREFORE Phi=Phi_"max" cos (omegat)`…(2) (Where `Phi_"max"` = maximum magnetic FLUX passing through the coil ) Now , we are given `Phi=1/2Phi_"max"` `therefore 1/2 Phi_"max"=Phi_"max" cos (omegat)` `therefore cos (omegat)=1/2` `therefore omegat =pi/3` `therefore (2pi)t=pi/3` `therefore t=1/6s`

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