1.

A circular current carrying loop of radius R, carries a current l. The magnetic field at a point on the axis of coll is (1)/(sqrt(8)) times the value of magnetic field at the centre. Distance of point from centre is

Answer»

`(R )/(SQRT(2))`
`(R )/(sqrt(3))`
`Rsqrt(2)`
R

Solution :FORCE on the dielectric `=(epsilon_(0)bv^(2)(k-1))/(2d)`
If rise due to this force be `x_(1)` then `=(epsilon_(0)bv^(2)(k-1))/(2d)=(DL)x_(1)pg`
Then `x_(2)` is the rise due to surface tension `T((1)/(r_(1))+(1)/(r_(2)))=T((1)/(oo)+(1)/(d//2))=(2T)/(d)=(x_(2))pg`
`x_(1)+x_(2)=(epsilon_(0)bv^(2)(k-1))/(2d^(2)Lpg)+(2T)/(dpg)=5+2=7mm`


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