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A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r is made from an iron plate of thickness 1/4. The relation between the moments of inertia IA and IB is (a) lA > IB (b) IA = IB (c)IA<IB (d) depends on the actual values of t and r. |
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Answer» (c) IA <IB Explanation: Let the density of iron plate be ρ. Mass of first disc m = πr²tρ M.I. = IA = ½mr² == ½πr²tρr² = ½πr4tρ Mass of second disc = M = π(4r)²(t/4)ρ = 4πr²tρ M.I. = IB = ½M(4r)² = ½4πr²tρ16r² = 32πr4tρ Clearly, IA < IB. |
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