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A circular disc of radius `0.2 m` is placed in a uniform magnetic fied of induction `(1)/(pi) ((Wb)/(m^(2)))` in such a way that its axis makes an angle of `60^(@)` with The magnetic flux linked with the disc isA. 0.08 WbB. 0.01 WbC. 0.02 WbD. 0.06 Wb |
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Answer» Correct Answer - C `A=pir^(2)=0.04pi` `phi=BA cos theta` `=(1)/(pi)xx0.04pixxcos 60^(@)=0.02Wb` |
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