A circular disc of radius 5m with a surface charge density ρs = 10sinφ is enclosed by surface. What is the net flux crossing the surface?(a) 3(b) 2(c) 1(d) 0This question was posed to me in an international level competition.My doubt is from Gauss Law in chapter Electrostatic Fields of Electromagnetic Theory

A circular disc of radius 5m with a surface charge density ρs = 10sin

1.	A circular disc of radius 5m with a surface charge density ρs = 10sinφ is enclosed by surface. What is the net flux crossing the surface?(a) 3(b) 2(c) 1(d) 0This question was posed to me in an international level competition.My doubt is from Gauss Law in chapter Electrostatic Fields of Electromagnetic Theory
Answer» The correct choice is (d) 0 The EXPLANATION: Q = ∫ ρsds = ∫∫ 10sinφ rdrdφ, on INTEGRATING with r = 0->5 and φ = 0->2π, we GET Q = ψ = 0.

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