1.

A circular disc X of radius R is made from an iron plate of thickness t, and another disc Y of radius 4R is made from an iron plate of thickness (t)/(4). Then the relation between the moment of inertia I_(X) and I_(Y) is :

Answer»

`I_(Y)=64I_(X)`
`I_(Y)=32I_(X)`
`I_(Y)=16I_(X)`
`I_(Y)=I_(X)`

Solution :Now mass `=M="Vol"xxrho=piR^(2).t.RHO`
M.I. of X is `I_(X)=(1)/(2)m_(1)R_(1)^(2).I_(X)=(1)/(2)piR^(2)rhot.R^(2).=(1)/(2)piR^(4)rhot""...(i)`
`I_(Y)=(1)/(2)pi(4R^(2))xx(t)/(4)rho(4R)^(2)`
`=32piR^(4)rhot.""...(II)`
`(I_(X))/(I_(Y))=(1)/(64)orI_(Y)=64I_(X)`.


Discussion

No Comment Found

Related InterviewSolutions