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A circular loop of metal wire of radius r is placed perpendicular to uniform magnetic field B. Half of the loop is folded about the diameter with constant angular velocity omega. If resistance of the loop is R then current in the loop is |
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Answer» zero, when `theta = 0` `phi= B xx (pi)/(2)+ Bxx (pir^(2))/(2) xx cos omegat` Magnitude of the emf induced can be written as follows: `E= |(dphi)/(dt)|= (Bpir^(2))/(2) xx omega sin omegat` `e= (B omegapir^(2))/(2) sin omegat` Or in terms of `theta` we can write it as follows: `e= (B omegapir^(2))/(2) sin sintheta` Current Clowing through the coil can be written as follows: `i= (e)/(R)` `implies i= (pir^(2)B omega)/(2R)sintheta` We can SEE that options (a) and (d) are correct. |
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