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A Circular metal of are 0.03 m^(2) rotates in a uniform magnetic field of 0.4 T.The axis of rotation passes through the centre and perpendicular to its plane and is also parallel to the field .If the disc completes.20 revolution in one second and the resistance of the disc is 4 Omega .calculate the induced between the axis and the rim and induced curent flowing in the disc. |
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Answer» Solution :`A-0.3 m^(2)`,B-0.4T:,f=20 rps:`R=4 Omega` Area covered in 1 sec =Area of the dis `xx` frequency =`0.3xx20=0.6 m^(2)` induced emf, `EPSILON=` Rate of CHANGE flux `=(dPhi_B)/(dt)=(d(BA))/(dt)=(0.4xx0.6)/1=0.24V` Induced current `i=(epsilon)/R=(0.24)/4=0.06A` |
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