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A city bus is carrying 70 passengers,some with50 paisetickets and the remaining with 1 rupee tickets. if tthe total amount recieved by the conductor was 56 ,find the number of passengers of each type |
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Answer» Answer: 28 and 42 Step-by-step explanation: let the two types of passengers be X and y where type x passenger takes Rs. 0.50 ticket and type y passenger takes Rs. 1 ticket total number of passengers = 70 x + y = 70 equation (1) total amount collected by conductor = 56 0.50x + 1Y = 56 equation (2) subtract equation (1) - (2) x + y - (0.50x + y) = 70 - 56 x + y - 0.50x - y = 14 0.50x = 14 x = 14 / 0.50 x = 28 substitute x = 28 in equation (1) x + y = 70 28 + y = 70 y = 70 - 28 y = 42 therefore number of passengers with 0.50 paise tickets are 28 number of passengers with Rs. 1 tickets are 42 Hope you GET your answer |
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