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A class A amplifier with RC = 3.3 kand RE = 1.2 khas a VCC = 20 V. Find IC(sat).(a) 4.4mA(b) 6.1mA(c) 20mA(d) 16.7mAI have been asked this question during an online exam.This question is from Classification of Output Stages in division Differential and Multistage Amplifiers of Electronic Devices & Circuits

Answer» RIGHT option is (a) 4.4mA

Explanation: Since, at saturation region, Vcc = 0 V, so Vcc will DROP across Rc and RE only.

here, Rc + RE = 3.3 k ohm + 1.2 k ohm,

= 4.5 k ohm,

IC(sat) = Vcc/(4.5 k ohm),

= 20/(4.5 k ohm) = 4.44 mA.


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