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A clock with a metallic pendulum gains 5 s each day at a temperature of `15^@C` and loses 10 s each day at a temperature of `30^@C`. Find the coefficient of thermal expansion of the pendulum metal.A. `(1)/(86400)//^@C`B. `(1)/(43200)//^@C`C. `(1)/(14400)//^@C`D. `(1)/(28800)//^@C` |
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Answer» Correct Answer - A Loss of time due to heating a pendulum is given as `DeltaT=(1)/(2)alphaDeltathetaT` `implies12.5=(1)/(2)xxalphaxx(25-0)^@Cxx86400` `implies alpha=(1)/(86400)//^(@)C ` |
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