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A closed organ pipe of length `L` and an open organ pipe contain gass of densities `rho_(1)` and `rho_(2)`, respectively. The compressibility of gass are equal in both the pipes. Both the pipes are vibrating in their first overtone with same frequency . The length of the open orange pipe is (a) `(L)/(3)` `(4l) / (3)` (c ) `(4l)/(3)sqrt((rho_(1))/(rho_(2)))` (d) `(4l)/(3)sqrt((rho_(2))/(rho_(1)))` |
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Answer» `f _(C) = (nu)/(4((l_(0))/(2))) = (nu)/(2l_(0)) = f_(0) =f` (both first overtone) or `3((nu_(C))/(4L)) = 2((nu_(0))/(2l_(0)))` `:. l_(0) = (4)/(3) (nu_(0)/(nu_(C)))L = (4)/(3) (sqrtB//rho_(2))/(sqrtB//rho_(1)) L` = `(4)/(3) sqrt((rho_(1))/(rho_(2))) L` Hence, the correct option is (C). |
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