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A source `S` and a detector `D` high frequency waves are a distance `d` apart on the ground. The direct wave from `S` is found to be in phase at `D` with the wave from `S` that is reflected from horizontal layer at an altitude `H`. The incident and reflected rayes make the same angle with the reflecting layer. When the layer rises a distance `h`, no signal is detected at `D` . Negle ct absorption in the atmosphere and find the relation between d,h, `H` and the wavelength `lambda` of the waves. |
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Answer» Correct Answer - A::B::D `2 sqrt(H^(2) + d^(2)//4) - d = n lambda` ..(i) Now, `2 sqrt((H + h)^(2) + d^(2)//4) - d = n lambda + (lambda)/(2)` ..(ii) Solving these two equations, we get `lambda = 2 sqrt(4(H + h)^(2) + d^(2)) - 2sqrt(4 H^(2) + d^(2))` |
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