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A cylindrical tube, open at both ends, has a fundamental frequency `f` in air . The tube is dipped vertically in water so that half of its length is in water. The fundamental frequency of the air column is now (a) `f // 2` (b) `3 f // 4` (C ) `f` (d) `2f` |
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Answer» Initially , the tube was open at both ends and then it is closed. `f_(0) = (nu)/2l_(0)` and `f _(C) = (nu)/(4l_(C))` Since, tube is half dipped in water , `l_(C) = (l_(0))/(2)` `f _(C) = (nu)/(4((l_(0))/(2))) = (nu)/(2l_(0)) = f_(0) =f` Hence, the correct option is (C ). |
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