A closed vessel contains a mixture of two diatomic gases A and B.Molar massof A is 16 timesthat of Band mass of gas A. contained in the vessel is 2 times that of B . Then

A closed vessel contains a mixture of two diatomic gases A and B.Molar

1.	A closed vessel contains a mixture of two diatomic gases A and B.Molar massof A is 16 timesthat of Band mass of gas A. contained in the vessel is 2 times that of B . Then
Answer» AVERAGE kinetic energy per molecule of gas A is equal to that of gas B. root mean square value of translational velocity of gas B is fourtimesthat of A. root mean square value of translational VELOCITYOF gas B is fourtimesthat of A. number of molecules of gas Bin the CYLINDER is eight times that of gas A. Solution :Average KE per molecule = ` 5/2 kT ` Itdependsonlyon temperature. ` v_(rmsA) = sqrt((3RT)/(M_(A)))` ` v_(rms B) = sqrt((3RT)/(M_(B)) = sqrt((3RT)/(M_(A)//16)) = 4 v_(rms)A ` ` n_(A) = m_(A)/(M_(A) ,n_(B) = m_(B)/(M_(B) = (M_(A)//2)/((M_(A)//16)) = 8 NA ` ` P_(B) = ( n_(B)/(n_(A) + n_(B))) P_(0) , P_(A)= ( n_(A)/(n_(A)+ n_(B))) P_(0)` ` RightarrowP_(B) = 8 P_(A)`

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A closed vessel contains a mixture of two diatomic gases A and B.Molar massof A is 16 timesthat of Band mass of gas A. contained in the vessel is 2 times that of B . Then

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