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A closely wound solenoid of 800 turns and area of cross section 2.5xx10^(-4)m^2 carries a current of 3.0 A . Explain te sense in which the solenoid acts like a bar magnet . What is its associated magnetic moment ?

Answer»

Solution :`N = 800, A = 2.5 xx10^(-4) m^2, I = 3.0 A, m = ? `
` m = ANI = 2.5 xx10^(-4) xx800xx3.0=7.5 xx8xx10^(-2) =0.600 Am^2`
The field of SOLENOID is UNIFORM along the axis , and for short solenoid, it is similar to that of a BAR magnet and the polarity depends on the direction of circulation of current .


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