InterviewSolution
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InterviewSolution
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A closely wound solenoid of 800 turns and area of cross section 25 xx 10^(-4)m^(2) carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment? |
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Answer» Solution :Current carrying solenoid ACTS like a bar magnet placed on its axis with `overset(to) (m) bot overset(to) (A)` (where `overset(to) (A) =` area vector of cross-section of current carryingsolenoid). Now, magnetic dipole moment of current carrying solenoid is given by, `overset(to) (m_(s) ) = NIoverset(to) (A) ""...(1)` `therefore m_(s) = NIA ""...(2)` `therefore m_(s) = (800) (3) (2.5 XX 10^(-4) )` `therefore m_(s) = 0.6 J//T (= Am^(2) )""...(3)` Here direction of `overset(to) (A)` is determined from the sense of current by using LAW of right handed screw.  Here, magnetic fields produced by coaxial current carrying solenoid and bar magnet shown in above figure have same patterns. |
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