1.

A closest distance of approach of an `a` particle travelling with a velocity `V` towards `Al_(13)` nucleus . `d` . The closest distacne of approach of an alpha particle travelling with velocity `4V` toward `Fr_(26)` nucleus isA. `d//2`B. `d//4`C. `d//8`D. `d//16`

Answer» Correct Answer - C
`1/2mv^(2)=1/4piepsilon_(0)xx(q_(1)q_(2))/r: raz^(2)/v^(2)`


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