A clsoed organ pipe and an open organ pipe of same length produce 2 beats /second while vibrating in their fundamental modes. The length of the open organ pipe is halved and that of closed pipe is doubled . Then the number of beats produced per second while vibrating in the fundamental mode is :

A clsoed organ pipe and an open organ pipe of same length produce 2 be

1.	A clsoed organ pipe and an open organ pipe of same length produce 2 beats /second while vibrating in their fundamental modes. The length of the open organ pipe is halved and that of closed pipe is doubled . Then the number of beats produced per second while vibrating in the fundamental mode is :
Answer» 8 7 2 6 Solution :In first case `f_(0) - f_(c)= 2`. `(V)/(2l) - (v)/(4l) = 2 ` `(v)/(4l) = 2 rArr (v)/(l) = 8 ` . When length of open organ pipe is havlved and that of closed organ pipe is doubled then beat frequency will `be F._(0) - f._(c) = (v)/(2. (i)/(2))= (v)/(4.2) = (v)/(l) - (v)/(8l)` = `(7)/(8) (v)/(l)` = `(7)/(8) xx 8 = 7 ` HZ. so correct choice is b.

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A clsoed organ pipe and an open organ pipe of same length produce 2 beats /second while vibrating in their fundamental modes. The length of the open organ pipe is halved and that of closed pipe is doubled . Then the number of beats produced per second while vibrating in the fundamental mode is :

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