1.

A coil has an area of 0.05 m^2 and has 800 turns. After placing the coil in a magnetic field of strength 4 xx 10^(-5) "Wb/m"^2 perpendicular to the field the coil is rotated through 90^@ in 0.1 s. The average emf induced is ____

Answer»

zero
0.016 V
0.01 V
0.032 V

Solution :`N Deltaphi=N(phi_2-phi_1)`
`=N(AB cosphi_2 -AB COS phi_1)`
`=NAB (cos theta_2 - cos theta_1)`
`=800xx5xx10^(-2)xx4xx10^(-5)("cos"pi/2- cos0^@)`
`=160xx10^(-5)[0-1]`
`=-160xx10^(-5)` Wb
`therefore epsilon=-(N Deltaphi)/(DELTAT)=(160xx10^(-5))/0.1 =160xx10^(-4)`
`therefore epsilon` =0.016 V


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