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A coil has an inductance of 0.7 H and is joined in series with a resistance of 220 ohm. Find the wattless component of current in the circuit, when an alternating e.m.f. of 220 V at a frequency of 50 Hz is supplied to it.A. `0.2 A`B. `0.4A`C. `0.5A`D. `0.7A` |
Answer» Correct Answer - C `X_(L)=omega_(L)=2pifL=220 Omega` `phi=tan^(-1)((X_(L))/R)= tan^(-1).(220)/(200)=45^(@)` `I=E/(sqrt(R^(2)+X_(L)^(2)))=220/((220)^(2)+(220)^(2))` Wattless component of current `=I sin phi` `=1/(sqrt(2)). Sin 45^(@)=0.5A` |
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