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A coil has an inductance of 0.7 H and is joined in series with a resistance of 220 ohm. Find the wattless component of current in the circuit, when an alternating e.m.f. of 220 V at a frequency of 50 Hz is supplied to it. |
Answer» `tan phi = (X_(L))/(R ) = (omega L)/(R ) = (2 pi xx 50 xx 0.7)/(220) = 1` `:. phi = 45^(@), Z = sqrt(R^(2) + X_(L)^(2)) = sqrt(220 + 220^(2))` `= 220 sqrt(2) Omega` Wattless component of current `= I_(v) sin phi` `= (E_(v))/(Z) sin 45^(@) = (220)/(220sqrt(2)) xx (1)/(sqrt(2)) = 0.5 A` |
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