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A coil having 200 turns has a surface of 0.15 m^2. A magnetic field of strength 0.2 T applied perpendicular to this changes to 0.6 T in 0.4 s. then the induced emf in the coil is …. V. |
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Answer» 45 `B_1=0.2 T , B_2=0.6T` `DELTAT`=0.4 s MAGNITUDE of INDUCED emf `epsilon=N (Deltavarphi)/(Deltat)` `=N(AB_2-AB_1)/(Deltat)` `=NA(B_2-B_1)/(Deltat)` `=200xx0.15xx(0.6-0.2)/0.4` = 30 V |
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