1.

A coil having 200 turns has a surface of 0.15 m^2. A magnetic field of strength 0.2 T applied perpendicular to this changes to 0.6 T in 0.4 s. then the induced emf in the coil is …. V.

Answer»

45
30
15
60

Solution :`A=0.15 m_2, N=200`
`B_1=0.2 T , B_2=0.6T`
`DELTAT`=0.4 s
MAGNITUDE of INDUCED emf
`epsilon=N (Deltavarphi)/(Deltat)`
`=N(AB_2-AB_1)/(Deltat)`
`=NA(B_2-B_1)/(Deltat)`
`=200xx0.15xx(0.6-0.2)/0.4` = 30 V


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