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A coil of `200Omega` resistance and `1.0H` inductance is conneted to an `AC` source of frequency `200//2pi Hz`. Phase angle between potential and current will beA. `30^(@)`B. `90^(@)`C. `45^(@)`D. `0^(@)` |
Answer» Correct Answer - C `tan phi=(X_(L))/R=(2pivL)/R` `=(2pixx200/(2pi)xx1)/200=1 implies phi=45^(@)` |
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