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A coil of `40 H` inductance is connected in series with a resistance of `8` ohm and the combination is joined to the terminals of a `2 V` battery. The time constant of the circuitA. `5s`B. `1//5s`C. `40s`D. `20s` |
Answer» Correct Answer - A Time constant of `L-R` circuit is, `tau=L/R` Here, `L=40 H, R=8 Omega, E=2V` `:. tau =40/8=5s` |
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