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A coil of 800 turns and 50 cm^(2) area makes 10 rps about an axis in its own plane in a magnetic field of 100 gauss perpendicular to this axis. What is the instantaneous induced emf in the coil? |
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Answer» Solution :`A=50cm^(2)=50 XX 10^(-4)m^(2)` n=10 rps, N=800 B= 100 gauss= `100xx10^(-4)T=10^(-2)T` Now, `epsilon=epsilon_(0) sin omegat=NBA omega sin omegat` `=800 xx 10^(-2) xx 50 xx 10^(-4) xx 2pi xx 10sin(20PI t)` or `epsilon-2.5 sin(2pi t)` volt |
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