Saved Bookmarks
| 1. |
A coil of area 0.05m^2 and 500 turns is placed in a magnetic field of strength 4xx10^-5tesla. If it is rotated through 90^@ in 0.1sec, then what is the magnitude of e.m.f. induced in the coil? |
|
Answer» SOLUTION :`E = (dphi)/DT = nAB/t = (500xx5xx10^-2xx4xx10^-5)/10^-1` `THEREFORE e = 10^-2V` = 10MV.` |
|