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A coil of inductance 0.2 henry is connected to 600 volt battery. At what rate, will the current in the coil grow when circuit is completed? |
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Answer» Solution :As the BATTERY and INDUCTOR are in parallel, at any INSTANT, EMF of the battery and self emf in the inductor are equal `|e|=L(DI)/(dt)` or `(dI)/(dt)=(|e|)/(L)=(600 V)/(0.2H)=3000 As^(-1)` |
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