1.

A coil of inductance 0.50 H and resistance 100 Omega is connected to a 240 V, 50 Hz ac supply. What is the time lag between the voltage maximum and the current maximum ?

Answer»

Solution :We have `tan PHI = ( X_(L ) - X_(C ))/( R )`
`:. tan phi= ( 2pi f L )/( R ) ( :.` Here, `X_(C ) = 0` )...(2)
`= ( 2 xx 3.14 xx 50 xx 0.5 ) /( 100)`
`:. tan phi= 1.57`
F= 50 Hz
`T = (1)/( 50) = 0.02 sec`
PHASE difference( rad )Time
` 2pi `0.02
`1.57 xx (pi )/( 180)`(t )
` t = ( 0.02 xx 1.57 ) /( 2pi )xx ( pi )/( 180)`
`= 3.2 xx 10^(-3) = 3.2 ms `


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