1.

A coil of inductance 0.50 H and resistance 100 Omega is connected to a 240 V, 50 Hz ac supply. What is the maximum current in the coil ?

Answer»

SOLUTION :`I_(m) = ( V_(m))/( |Z|)`
`= ( SQRT(2) V_(rms))/( sqrt( R^(2) + X_(L)^(2)))`
`:. I_(m) = ( sqrt(2)V_(rms))/(sqrt( R^(2) + 4pi^(2) f^(2) L^(2)))``( :. X_(L) = omega L = 2pi f L ) `...(1)
`= ( ( 1.414 ) ( 240) )/( sqrt(( 100)^(2) + ( 4) ( 3.14)^(2) ( 50)^(2) ( 0.5)^(2)))`
=1.82A


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