A coil of inductance 0.50 H and resistance `100Omega` is connected to a 240 V, 50Hz ac supply. what is the maximum current in the coil?

A coil of inductance 0.50 H and resistance `100Omega` is connected to

1.	A coil of inductance 0.50 H and resistance `100Omega` is connected to a 240 V, 50Hz ac supply. what is the maximum current in the coil?
Answer» Given, Inductance L = 0.50 H Resistance `R = 100 Omega` `V_("rms")=240V, f=50Hz` Impedance of circuit `Z=sqrt(R^(2)+X_(L)^(2))=sqrt(R^(2)+(2pi fL)^(2))` `= sqrt((100)^(2)+(2xx3.14xx50xx0.50)^(2))` `= 186.14 Omega` the rms value of current `I_("rms")=(V_("rms"))/(z)=(240)/(186.14)1.29 A` the maximum value of current in the circuit `I_(0)=sqrt(2)I_("rms")=1.414xx1.29=1.824A`

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A coil of inductance 0.50 H and resistance `100Omega` is connected to a 240 V, 50Hz ac supply. what is the maximum current in the coil?

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