1.

A coil of N turns and area A is placed in a uniform transverse magnetic field B in such a way that vecA and vecB are parallel. If the plate in turned through 180^@ about its one of the diameter in 2 seconds then the (i) change of magnetic flux through the coil is ? (ii) rate of change of flux is the coil is ?

Answer»

SOLUTION :`Deltaphi=phi_2-phi_1`
`=NBA (COS theta_2-costhata_1)`
`= NBA(cos180^@-cos0)`
=NBA[-1-1]
=-2NBA
(ii)Rate of charge of flux is
`(Deltaphi)/(Deltat)=(-2NBA)/(2)`
=-NBA


Discussion

No Comment Found

Related InterviewSolutions