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A coil of N turns and area A is placed in a uniform transverse magnetic field B in such a way that vecA and vecB are parallel. If the plate in turned through 180^@ about its one of the diameter in 2 seconds then the (i) change of magnetic flux through the coil is ? (ii) rate of change of flux is the coil is ? |
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Answer» SOLUTION :`Deltaphi=phi_2-phi_1` `=NBA (COS theta_2-costhata_1)` `= NBA(cos180^@-cos0)` =NBA[-1-1] =-2NBA (ii)Rate of charge of flux is `(Deltaphi)/(Deltat)=(-2NBA)/(2)` =-NBA |
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