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A coil of resistance 20Omegaand self-inductance 5 H connected with battery 100 V. What will be the value of energy stored ? |
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Answer» 31.25 J `=1/2LI^2` `=1/2L[E/R]^2 "" [because I=E/R]` `=1/2xx5xx[100/20]^2=1/2xx5xx25`=62.5 J |
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