1.

A coil of resistance R and inductance L is joined with a battery of E volt. The current passing through it will be ………..

Answer»

`E/R`
`E/L`
`sqrt(E^2/(R^2+L^2))`
`sqrt((EL)/(R^2+L^2))`

Solution :When D.C. EMF of E VOLT applied to a CIRCUIT, `omega = 0 thereforeX_L = omegaL = 0`. So inductor act as a conductor.
`therefore` Impedance of circuit
`therefore I=E/"|Z|" "" |Z|=R`
`therefore I=E/R`


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