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A coil of wire of radius r has 600 turns and a self inductance of 108 mH. The self inductance of a coil with same radius and 500 turns is

Answer» <html><body><p>80mH<br/>75mH<br/>108mH <br/>90mH</p>Solution :Self <a href="https://interviewquestions.tuteehub.com/tag/inductance-1042546" style="font-weight:bold;" target="_blank" title="Click to know more about INDUCTANCE">INDUCTANCE</a> of the coil .<br/> `L=(mu_(0)<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>^(2)pir)/2`<br/> `LpropN^(2)r`<br/>`L_(1)/L_(2)=(N_(1)/N_(2))^(2)(r_(1)/r_(2))`<br/>`implies (<a href="https://interviewquestions.tuteehub.com/tag/108-266746" style="font-weight:bold;" target="_blank" title="Click to know more about 108">108</a>)/(L_(2))=((<a href="https://interviewquestions.tuteehub.com/tag/600-329515" style="font-weight:bold;" target="_blank" title="Click to know more about 600">600</a>)/(500))^2((r)/(r))`<br/> `thereforeL_(2)=75mH.`</body></html>


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