1.

A coil with 1500 turns, a radius of 5.0 cm and a resistance of 12 Omega surrounds a solenoid with 240 turns // cm and a radius of 4 cm , see figure. The current in the solenoid changes at aconstant rate from 0 to 20 A in 0.10 s. Calculate the magnitude of the induced current (in mA) in the 1500 turn coil (pi^(2)=10 Neglect self inductance of the coil).

Answer»


Solution :`varepsilon=150xxd/dt(mu_(0)NI)xxpxx((4.5)/100)^(2)`
`=150xx4pixx10^(-7)xx(230xx10^(2))/100xx2/0.1xxpixx(4.5xx4.5)/10^(4)`
`i=varepsilon/12=(600pi^(2)xx460xx10^(3)xx10^(-7))/12xx(4.5)^(2)/10^(4)`
`=0.04657500xx10^(-6)`
`approx 5A`


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