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A coin is at rest at bottom of a tank filled with liquid. A ray of light coming towards surface will move on the surface after incident on it, then what is the speed of light in liquid ? |
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Answer» `2.4xx10^8 ms^(-1)`  Length of hypotenuse of RIGHT ANGLE `triangle`1ABC is 5. `therefore (1)/(mu)=(sini)/(SIN 90^@)` …... (`because` Refractive index of LIQUID =`mu`, refractive index of air =1) `therefore mu =(1)/(sini)=5/3` Now speed `v=(c)/(mu)=(3xx10^8)/(5/3)=1.8xx10^8` m`//`s |
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