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A coin is tossed 4 times. The probability that at least one head turns up, isA. \(\frac{1}{6}\)B. \(\frac{2}{16}\)C. \(\frac{14}{16}\)D. \(\frac{15}{16}\) |
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Answer» Correct answer is D. Given: n = 4 p(getting atleast one head) = ? • 0 head : HHHH • 1 head : HTTT THTT TTHT TTTH • 2 heads : HHTT HTHT HTTH THHT THTH TTHH • 3 heads : HHHT HHTH HTHH THHH • 4 heads : HHHH Total ouctomes = 16 Outcomes containing atleast 1 head = 15 P(getting atleast 1 head) = \(\frac{15}{16}\) |
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