1.

A coin is tossed 4 times. The probability that at least one head turns up, isA. \(\frac{1}{6}\)B. \(\frac{2}{16}\)C. \(\frac{14}{16}\)D. \(\frac{15}{16}\)

Answer»

Correct answer is D.

Given:

n = 4

p(getting atleast one head) = ?

• 0 head : HHHH

• 1 head : HTTT

THTT

TTHT

TTTH

• 2 heads : HHTT

HTHT

HTTH

THHT

THTH

TTHH

• 3 heads : HHHT

HHTH

HTHH

THHH

• 4 heads : HHHH

Total ouctomes = 16

Outcomes containing atleast 1 head = 15

P(getting atleast 1 head) = \(\frac{15}{16}\)



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