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In a class, 60% of the students read mathematics, 25% biology and 15% both mathematics and biology. One student is selected at random. What is the probability that he reads mathematics if it is known that he reads biology?A. \(\frac{2}{5}\)B. \(\frac{3}{5}\)C. \(\frac{3}{8}\)D. \(\frac{5}{8}\) |
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Answer» Correct answer is B. Given: 60% of the students read mathematics, 25% biology and 15% both mathematics and biology That means, Let the event A implies students reading mathematics, Let the event B implies students reading biology, Then, P(A) = 0.6 P(B) = 0.25 P(A∩B) = 0.15 We, need to find P(A/B) = P(A∩B)/ P(B) \(\Rightarrow\) \(\frac{0.15}{0.25}=\frac{3}{5}\) |
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