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A coin is tossed 5 times. What is the probability that a head appears an even number of times? |
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Answer» As the coin is tossed 5 times the total number of outcomes will be \(2^5=32.\) And we know that the favourable outcomes of a head appearing even number of times will be, That either the head appears 0, 2 or 4 times so, The respective probabilities will be:- \(5_{C_0}\) + \(5_{C_2}\) + \(5_{C_4}\) = 16 Thus, the probability \(=\frac{The\,favourable\,outcomes}{The\,total\, number\, of\, outcomes}\) \(\Rightarrow=\frac{16}{32}=\frac{1}{2}\) Hence, the probability is 1/2. |
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