1.

A coin is tossed 600 times with the frequencies as : heads : 342 and tails : 258 If a coin is tossed at random , what is the probability of getting (i) a head ? `" "` (ii) a tail ?

Answer» Total number of trials = 600 .
Number of heads = 342.
Number of tails = 258.
On tossing a coin , let `E_(1)` and `E_(2)` be the events of getting a head and of getting a tail respectively . Then ,
(i) P(getting a head ) = P `(E_(1))`
`= ("number of heads coming up")/("total number of trials")`
`= (342)/(600) = (57)/(100) = 0.57` .
(ii) P(getting a tail ) = `P (E_(2))`
`= ("number of tails coming up")/("total number of trails")`
`(258)/(600) = (43)/(100) = 0.43`


Discussion

No Comment Found

Related InterviewSolutions