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A coin is tossed 600 times with the frequencies as : heads : 342 and tails : 258 If a coin is tossed at random , what is the probability of getting (i) a head ? `" "` (ii) a tail ? |
Answer» Total number of trials = 600 . Number of heads = 342. Number of tails = 258. On tossing a coin , let `E_(1)` and `E_(2)` be the events of getting a head and of getting a tail respectively . Then , (i) P(getting a head ) = P `(E_(1))` `= ("number of heads coming up")/("total number of trials")` `= (342)/(600) = (57)/(100) = 0.57` . (ii) P(getting a tail ) = `P (E_(2))` `= ("number of tails coming up")/("total number of trails")` `(258)/(600) = (43)/(100) = 0.43` |
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