1.

A coins kept on a horizontal rotating disc has its centre at a distance of 0.25 m from the axis of rotation of the disc .If `mu is 0.2`, then the angular velocity of the disc at which the coion will slip off, `(g=9.8m//s^(2))`A. `3.8 rad//s`B. `2.8 rad//s`C. `4.8 rad//s`D. `5.8 rad//s`

Answer» Correct Answer - B
`v=sqrt(mu g r )`
`therefore r omega =sqrt mu g r `
`therefore omega = sqrt (mu g)/(r)`


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