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A colliison between reactant molecules must occur with a certain minimum energy before it is effective in yielding Product molecules. This minimum energy is called activation energy `E_(a)` Large the value of activation energy, smaller the value of rate constant `k`. Larger is the value of activation energy, greater is the effect of temperature rise on rate constant `k`. `E_(f) =` Activation energy of forward reaction `E_(b) =` Activation energy of backward reaction `Delta H = E_(f) - E_(b)` `E_(f) =` threshold energy For the following reaction at a particular temperature, according to the equations `2N_(2)O_(5) rarr 4NO_(2)+O_(2)` `2NO_(2) + (1)/(2)O_(2) rarr N_(2)O_(5)` The activation energies are `E_(1)` and `E_(2)`, respectively. ThenA. `E_(1) gt E_(2)`B. `E_(1) lt E_(2)`C. `E_(1) = 2E_(2)`D. `sqrt(E_(1)E_(2)^(2)) = 1` |
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Answer» Correct Answer - A The reactions: (i) `2N_(2)O_(5) rarr 4NO_(2) + O_(2)` is of `(C rarr A+B)` type. (ii) `2NO_(2) + (1)/(2)O_(2)rarrN_(2)O_(5)` is of `(A+B rarr C)` type. And for the reaction `(A + B rarr C)`, `E_(a(f))` is `249` and `E_(a(b))` is `279 kJ mol^(-1)`. |
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